16. Complete Activity 10.16 (Page 122).
• Consider two children, say A and B. Let us say they weigh the same. Both start climbing up a rope separately. Both reach a height of 8 m. Let us say A takes 15 s while B takes 20 s to accomplish the task.
• What is the work done by each?
• The work done is the same. However, A has taken less time than B to do the work.
• Who has done more work in a given time, say in 1 s?
Answer:
Let the mass of each boy be m kg.
Height climbed by each is 8 m.
Work done by A = work done by B = mg(8) = 8mg.
Time taken by A = 15 s.
Power of A = Work done/time = 8mg/15.
Time taken by A = 20 s.
Power of B = Work done/time = 8mg/20.
Power of A/Power of B = 8mg/15 ÷ 8mg/20 = 8mg/15 × 20/8mg = 4/3
Therefore, the work done by A in 1 s or the power of A is more.
“• Consider two children, say A and B. Let us say they weigh the same. Both start climbing up a rope separately. Both reach a height of 8 m. Let us say A takes 15 s while B takes 20 s to accomplish the task.
• What is the work done by each?
• The work done is the same. However, A has taken less time than B to do the work.
• Who has done more work in a given time, say in 1 s?” – Solved.
Related Links:
Solution to Activity 10.1
Solution to Activity 10.2
Solution to Activity 10.3
Solution to Activity 10.4
Solution to Activity 10.5
Solution to Activity 10.6
Solution to Activity 10.7
Solution to Activity 10.8
Solution to Activity 10.9
Solution to Activity 10.10
Solution to Activity 10.11
Solution to Activity 10.12
Solution to Activity 10.13
Solution to Activity 10.14
Solution to Activity 10.15
Solution to Activity 10.16
Solution to Activity 10.17
Solutions to Chapter 10 Work and Energy
